On - line Appendix for In fl uencing Connected Legislators
نویسنده
چکیده
In this appendix we present the proofs omitted in “Influencing Connected Legislators.” Marco Battaglini Cornell University and EIEF Ithaca, NY 14853 [email protected] Eleonora Patacchini Cornell University Ithaca, NY 14853 [email protected] 1 Proof of Lemma 1 Let φ be the dimensional column vector of voting probabilities with th element equal to . Define η : → as η(φ s) = φ−F(φ s), where s =(sA sB) and F(φ s) is a column vector with th element equal to 12 +Ψ 3 ()− () + (φ) + P (2 − 1) ́ , as defined in (5) in Section 3.1. The equilibrium probabilities φ(s) are defined as the solution of η(φ∗ s) = 0. The fact that the solution of this system exists follows from the Brower fixed-point theorem as argued in Section 3. Since, by Assumption 1, Ψ ( + + (2 )) 12, the solution is interior in (0 1). To show uniqueness of an equilibrium of the voting stage with policy motivated legislators for Ψ sufficiently small, let kk be the norm kk = X || for any ∈ . We have: °°F(φ s)−F(φ0 s)°° ≤ ΨÃ ·X ̄̄̄̄ ̄ Z X (x) ̄̄̄̄ ̄ + 2X 3X ́ ̄̄ − ̄̄ ! ≤ Ψ 3 · X (| − |) + 2 X ̄̄ − ̄̄ ́ ≤ Ψ ( + 2) kφ−φ0k where we use the fact that ̄̄ (x) ̄̄ 1 for any x, and X ≤ 1 for any . For any 1, we therefore have °°F(φ s)−F(φ0 s)°° ≤ · kφ−φ0k for Ψ sufficiently small. We can therefore conclude that there is a Ψ1 such that F(φ s) is a contraction in [0 1] with a unique fixed-point in (0 1) for Ψ ≤ Ψ1. We now turn to the derivatives of the voting probabilities. The implicit function theorem implies that the solution is differentiable in at s s if (η) is invertible in a neighborhood of (s sφ(sA sB)), where φ(sA sB) solves η(φ s s) = 0 (the expression (η) represents the Jacobian of η with respect to φ). It is easy to verify that (η) = h − Ψ2 e i, where e is a × matrix with element equal to e = ¡ + (φ)¢. Let ∗ be the largest eigenvalue of e achieved for some φ (this is well defined and bounded since ( e ) is continuos in φ in and the space of feasible φ is compact). Theorem III* of Debreu and Herstein [1953] implies that h − Ψ2 e i−1 exists and is nonegative for Ψ ≤ (2∗)−1 = Ψ2. The Jacobian of is then [] = Ψ · () h − Ψ2 e i−1 1 where 1 is a -dimensional vector equal to zero except at the th dimension in which it is equal to one. Since h − Ψ2 e i−1 is nonnegative with at least one strictly positive element for Ψ ≤ Ψ2, it follows that X = [] · 1 0 for large enough. To verify concavity with respect to s, let be the Hessian of . Consider first its diagonal entries for any . We can write: = Ψ ⎢⎢⎣ ( ) + 2 P + P 3P (φ) 3 ́3 ́ + (φ) ́ ⎥⎥⎦ (1)
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